P
RAMANA c Indian Academy of Sciences Vol. 77, No. 4— journal of October 2011
physics pp. 759–764
The classification of single travelling wave solutions to the Camassa–Holm–Degasperis–Procesi equation for some values of the convective parameter
CHUN-YAN WANG∗, JIANG GUAN and BAO-YAN WANG
Department of Mathematics, Northeast Petroleum University, Daqing 163318, China
∗Corresponding author. E-mail: chunyanmyra@163.com
MS received 2 December 2010; revised 4 March 2011; accepted 21 March 2011
Abstract. By the complete discrimination system for the polynomial, we give the classification of single travelling wave solutions to the Camassa–Holm–Degasperis–Procesi equation for some values of the convective parameter.
Keywords. Complete discrimination system for the polynomial; single travelling wave solution;
Camassa–Holm–Degasperis–Procesi equation.
PACS Nos 02.30.Jr; 05.45.Yv; 03.65.Ge
1. Introduction
Classifications of single travelling wave solutions to some nonlinear differential equations have been obtained extensively by the complete discrimination system for polynomial method proposed by Liu [1–7]. Furthermore, Wang and Li [8] used Liu’s method and factorization method proposed by Cornejo-Pérez and Rosu [9–11] to give single solitary and multi-solitary solutions to some nonlinear differential equations. Yang [12] studied the classification of envelope solutions to SD equation by Liu’s method. In the present paper, we consider the Camassa–Holm–Degasperis–Procesi (CH–DP) equation which reads as
ut−c0ux+(b+1)uux−α2(ux xt+uux x x+buxux x)+γux x x =0, (1) where b is a convective parameter and b=1, b=0. Using the dynamical system approach, the bifurcation of travelling wave solutions to the CH–DP equation has been studied (see, for example, ref. [13] and the references therein). By Liu’s method, we shall give the classification of single travelling wave solutions to the CH–DP equation for some values of the convective parameter.
2. Classification of travelling wave solutions
Taking the travelling wave transformation u=u(ξ)andξ =x−ct , the CH–DP equation is reduced to the following ODE:
−(c+c0)u+(b+1)uu−α2(uu+buu)+(α2c+γ )u=0. (2)
This equation can be turned into the following first-order differential equation by integrat- ing it once and using y=(u)2as the new dependent variable:
y+pb(u)y+qb(u)=0, (3)
where pb(u)= u−(cb−γ /α−1) 2 and qb(u)= 2(c+cα0)2uu−(−cb−γ /α+1)u22−2C1, C1 is an integral constant. By the method of variation of constants, we can obtain the general solution of eq. (3) [6],
y=exp
−
pb(u)du
×
C2−
qb(u)exp
pb(u)du
du
, (4)
where C2is an integral constant. The solutions of u can be given from±(ξ−ξ0)= du
√y. When b = −1 and −2, we can easily give the classifications of single travelling wave solutions by using the discrimination system for two-order and three-order polynomial respectively. For saving space, we only consider the case of b = 3. Of course, we can give same treatment for other values of b.
Substituting the expressions of p3(u)and q3(u)into eq. (4), and performing the trans- formationv = u −c−γ /α2, the general solution can be obtained from the following quadrature:
±1
α(ξ−ξ0)=
vdv
v4+a3v3+a2v2+a0
, (5)
where a3=2c−23c0+38γα2, a2=C1−(c+c0) c+αγ2
, a0=C2α2.
Case 1. a0 =0. Denote=a23−4a2. There exist two cases to be discussed:
Case 1.1. If=0, the corresponding solutions are u = ±exp
±1
α(x−ct−ξ0)
+c0 3 − γ
3α2. (6)
Case 1.2. If >0 or <0, the corresponding solutions are u = ±1
2exp
±1
α(x−ct−ξ0)
+ c20
18−17γ2 18α4+cc0
6 + c0γ 18α2−cγ
6α2−C1 2
×exp
∓1
α(x−ct−ξ0)
+c0 3 − γ
3α2. (7)
Case 2. a0 =0. By the transformationw=v+a43, eq. (5) becomes
±1
α(ξ−ξ0)=
(w−a43)dw
w4+pw2+qw+r, (8)
where p= −38a32+a2, q =a833−a22a3, r =a0+a162a32−3a25643.Denote F(w)=w4+pw2+ qw+r and write its complete discrimination system as follows:
D1=4, D2= −p, D3=8r p−2 p3−9q2, D4=4 p4r−p3q2+36 pr q2−32r2p2−27
4 q4+64r3, E2=9q2−32 pr. (9)
Classification of single travelling wave solutions
Case 2.1. D4=0,D3=0,D2<0. Then F(w)=(w2+l2)2, and l>0. Hence D2= −p= −2l2 =3
8a32−a2<0, q =a33 8 −a2a3
2 =0.
So a3=0 or a3= ±4li .
Case 2.1.1. If a3=0, eq. (8) becomes
±1
α(ξ−ξ0)=
wdw
(w2+l2)2. (10)
The corresponding solutions are u = ±
exp
±2
α(x−ct−ξ0)
−l2+c 2+ γ
3α2 +c0
6. (11)
Case 2.1.2. If a3= ±4li , eq. (8) becomes
±1
α(ξ−ξ0)=
wdw (w2+l2)2 ±i
dw
w2+l2. (12)
The corresponding solutions are
±1
α(ξ−ξ0)=1 2ln
u−c
2 − γ 3α2 −c0
6 2
+l2
±i arctanu−2c−3αγ2 −c60
l . (13)
Case 2.2. D4 = 0,D3 = 0,D2 = 0. Then F(w) = w4. This case can be included in Case 1.
Case 2.3. D4 =0,D3 = 0,D2 >0,E2 > 0. Then F(w)= (w−w1)2(w+w1)2, and w1>0. It follows that
D2= −p=2w21= 3
8a23−a2, q= a33 8 −a2a3
2 =0.
Therefore, we have a3=0 or a3= ±4w1.
Case 2.3.1. If a3= ±4w1, then a0=0. It can be included in Case 1.
Case 2.3.2. If a3=0, eq. (8) becomes
±1
α(ξ−ξ0)=
dw w+w1
+w1
dw
(w−w1)(w+w1). (14) The corresponding solutions are
u = ±
w21±exp ±2
α(x−ct−ξ0)
+c+ γ
α2. (15)
Case 2.4. D4 =0,D3 >0,D2 >0. Then F(w)=(w−w1)2(w−w2)(w−w3), and 2w1+w2+w3=0, w2> w3. Since
p=w2w3−3w21= −3
8a32+a2, q = −2w1w2w3+2w13=a33 8 −a2a3
2 we have the following two kinds of solutions:
Case 2.4.1. If a3=4w1, then a0=0. It can be included in Case 1.
Case 2.4.2. If a3=4w1, eq. (8) becomes
±1
α(ξ−ξ0)=
√ dw
(w−w2)(w−w3) +
w1−a3 4
dw (w−w1)√
(w−w2)(w−w3). (16) Whenw1> w2andw > w2, or whenw1< w3andw < w3, we have
±1
α(x−ct−ξ0)
=ln|u+A+w1+
(u+A−w2)(u+A−w3)|
+
w1−c 2+c0
6 − 2γ 3α2
1
√(w1−w2)(w1−w3)
×ln [√
(u+A−w2)(w1−w3)−√
(w1−w2)(u+A−w3)]2
|u+A−w1|
. (17)
Whenw1> w2andw < w3, or whenw1< w3andw < w2, we have
±1
α(x−ct−ξ0)
=ln|u+A+w1+
(u+A−w2)(u+A−w3)|
+
w1−c 2+c0
6 − 2γ 3α2
1
√(w1−w2)(w1−w3)
×ln [√
(u+A−w2)(w3−w1)−√
(w2−w1)(u+A−w3)]2
|u+A−w1|
. (18)
Whenw2> w1> w3, we have
±1
α(x−ct−ξ0)
=ln|u+A+w1+
(u+A−w2)(u+A−w3)|
+
w1−c 2+c0
6 − 2γ 3α2
1
√(w2−w1)(w1−w3)
× arcsin(u+A−w2)(w1−w3)+(u+A−w3)(w1−w2)
|(u+A−w1)(w2−w3)| , (19) where A=2c+c60 +3αγ2.
Classification of single travelling wave solutions
Case 2.5. D4=0,D3=0,D2>0,E2 =0. Then F(w)=(w−w1)3(w+3w1). Since
p= −6w12= −3
8a23+a2, q =8w31= a33 8 −a2a3
2 , r = −3w14=a0+a2a23 16 −3a34
256 we have the following two kinds of solutions:
Case 2.5.1. If a3=4w1, then a0=0. It can be included in Case 1.
Case 2.5.2. If a3=4w1, eq. (8) becomes
±1
α(ξ−ξ0)=
√ dw
(w−w1)(w+3w1) +
w1−a3
4
dw (w−w1)√
(w−w1)(w+3w1)). (20) The corresponding solutions are
±1
α(x−ct−ξ0) =ln|u+A+w1+
(u+A−w1)(u+A+3w1)|
−(w1−c2+c60 −3α2γ2) 2w1
u+A+3w1
u+A−w1
, (21)
where A=2c+c60 +3αγ2.
Case 2.6. D2D3<0,D4=0. Then F(w)=(w−w1)2[(w+w1)2+s2]. Since
p = −2w21+s2= −3
8a32+a2, q = −2w1s2= a33 8 −a2a3
2 , r = w41+w12s2 =a0+a2a23
16 −3a43 256 we have the following two kinds of solutions:
Case 2.6.1. If a3=4w1, then a0=0. It can be included in Case 1.
Case 2.6.2. If a3=4w1, eq. (8) becomes
±1
α(ξ−ξ0)=
dw (w+w1)2+s2 +
w1−a3 4
dw (w−w1)
(w+w1)2+s2. (22)
The corresponding solutions are
±1
α(x−ct−ξ0)
=ln|u+A+w1+
(w+w1)2+s2| + (w1−2c+c60 −3α2γ2)
4w21+s2 ln
σ (u+A)+δ−
(w+w1)2+s2 u+A−w1
, (23)
where A=2c+c60 +3αγ2, δ= w21+s2 /
4w12+s2, σ =3w1/
4w12+s2.
Case 2.7. D2 > 0,D3 > 0,D4 > 0 or D2D3 > 0,D4 < 0 or D2D3 < 0,D4 > 0, the travelling wave solutions to CH–DP equation can be represented in terms of elliptical functions. For simplicity, they are omitted.
Remark. We must point out that the classification can be realized under the concrete parameters. For simplicity, we also omit them.
3. Conclusion
The complete discrimination system for polynomial method is a powerful method for exact solutions to nonlinear differential equations. By the method, we obtain the classification of single travelling wave solutions to CH–DP equation for some values of the convective parameter. These solutions show rich and varied constructions of the solutions to CH–DP equation.
Acknowledgements
The authors are grateful to the referee for the helpful suggestions. The project is supported by Scientific Research Fund of Education Department of Heilongjiang Province of China under Grant No. 11551020.
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