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Subject: Statistics

Paper: Multivariate Analysis

Module: More on Canonical Correlations

(2)

Development Team

Principal investigator: Dr. Bhaswati Ganguli, Professor, Department of Statistics, University of Calcutta

Paper co-ordinator: Dr. Sugata SenRoy,Professor, Department of Statistics, University of Calcutta

Content writer: Souvik Bandyopadhyay, Senior Lecturer, Indian Institute of Public Health, Hyderabad

Content reviewer: Dr. Kalyan Das,Professor, Department of Statistics, University of Calcutta

(3)

Development Team

Principal investigator: Dr. Bhaswati Ganguli, Professor, Department of Statistics, University of Calcutta

Paper co-ordinator: Dr. Sugata SenRoy,Professor, Department of Statistics, University of Calcutta

Content writer: Souvik Bandyopadhyay, Senior Lecturer, Indian Institute of Public Health, Hyderabad

Content reviewer: Dr. Kalyan Das,Professor, Department of Statistics, University of Calcutta

(4)

Development Team

Principal investigator: Dr. Bhaswati Ganguli, Professor, Department of Statistics, University of Calcutta

Paper co-ordinator: Dr. Sugata SenRoy,Professor, Department of Statistics, University of Calcutta

Content writer: Souvik Bandyopadhyay, Senior Lecturer, Indian Institute of Public Health, Hyderabad

Content reviewer: Dr. Kalyan Das,Professor, Department of Statistics, University of Calcutta

(5)

Development Team

Principal investigator: Dr. Bhaswati Ganguli, Professor, Department of Statistics, University of Calcutta

Paper co-ordinator: Dr. Sugata SenRoy,Professor, Department of Statistics, University of Calcutta

Content writer: Souvik Bandyopadhyay, Senior Lecturer, Indian Institute of Public Health, Hyderabad

Content reviewer: Dr. Kalyan Das,Professor, Department of Statistics, University of Calcutta

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Standardized variables

I Let there ber variables in the1st groupX1= (X1, . . . , Xr) ands variables in the2nd groupX2 = (Xr+1, . . . , Xr+s), with r ≤sand

E(X1) =µ1 andE(X2) =µ2 V ar(X1) = Σ11,V ar(X2) = Σ22 andCov(X1,X2) = Σ12 (orΣ021)

I Let Z1 = (z1, . . . , Zr)and Z2 = (Zr+1, . . . , Zr+s), where Zj = (Xj−µj)/σjj for j = 1, . . . , r+s.

with µj =E(Xj) andσjj =V ar(Xj).

I What is the effect of this standardization on the canonical correlation ?

(7)

Standardized variables

I Let there ber variables in the1st groupX1= (X1, . . . , Xr) ands variables in the2nd groupX2 = (Xr+1, . . . , Xr+s), with r ≤sand

E(X1) =µ1 andE(X2) =µ2 V ar(X1) = Σ11,V ar(X2) = Σ22 andCov(X1,X2) = Σ12 (orΣ021)

I Let Z1 = (z1, . . . , Zr)and Z2 = (Zr+1, . . . , Zr+s), where Zj = (Xj−µj)/σjj for j = 1, . . . , r+s.

with µj =E(Xj) andσjj =V ar(Xj).

I What is the effect of this standardization on the canonical correlation ?

(8)

Standardized variables

I Let there ber variables in the1st groupX1= (X1, . . . , Xr) ands variables in the2nd groupX2 = (Xr+1, . . . , Xr+s), with r ≤sand

E(X1) =µ1 andE(X2) =µ2 V ar(X1) = Σ11,V ar(X2) = Σ22 andCov(X1,X2) = Σ12 (orΣ021)

I Let Z1 = (z1, . . . , Zr)and Z2 = (Zr+1, . . . , Zr+s), where Zj = (Xj−µj)/σjj for j = 1, . . . , r+s.

with µj =E(Xj) andσjj =V ar(Xj).

I What is the effect of this standardization on the canonical correlation ?

(9)

Canonical corrletion for standardized variables

I The answer is of course

Corr(Z1,Z2) =Corr(X1,X2)

since correlations do not change with base and scale changes.

I However, the canonical variables will be different.

I In general, for standardized variables, with V ar(Z1) =ρ11, V ar(Z2) =ρ22 andCov(Z1,Z2) =ρ12,

Uj =p0jρ−1/211 Z1 and Vj =q0jρ−1/222 Z2,

with Corr(Uj, Vj) =p λj.

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Canonical corrletion for standardized variables

I The answer is of course

Corr(Z1,Z2) =Corr(X1,X2)

since correlations do not change with base and scale changes.

I However, the canonical variables will be different.

I In general, for standardized variables, with V ar(Z1) =ρ11, V ar(Z2) =ρ22 andCov(Z1,Z2) =ρ12,

Uj =p0jρ−1/211 Z1 and Vj =q0jρ−1/222 Z2,

with Corr(Uj, Vj) =p λj.

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Canonical corrletion for standardized variables

I The answer is of course

Corr(Z1,Z2) =Corr(X1,X2)

since correlations do not change with base and scale changes.

I However, the canonical variables will be different.

I In general, for standardized variables, with V ar(Z1) =ρ11, V ar(Z2) =ρ22 andCov(Z1,Z2) =ρ12,

Uj =p0jρ−1/211 Z1 and Vj =q0jρ−1/222 Z2, with Corr(Uj, Vj) =p

λj.

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Justification

Observe that

a0j(X1−µ1) = aj1(X1−µ1) +. . .+ajr(Xr−µr)

= aj1

√σ11(X1−µ1)

√σ11 +. . .+ajr

√σrr(Xr−µr)

√σrr

= aj1

√σ11Z1+. . .+ajr

√σrrZr

I DefineV =diag((σkk))k=1....,r.

I Thus ifaj is the coefficient of thejth canonical variateUj, ajV−1/2 is the coefficient of the corresponding canonical variate Uj of the standardized variables.

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Justification

Observe that

a0j(X1−µ1) = aj1(X1−µ1) +. . .+ajr(Xr−µr)

= aj1

√σ11(X1−µ1)

√σ11 +. . .+ajr

√σrr(Xr−µr)

√σrr

= aj1

√σ11Z1+. . .+ajr

√σrrZr

I DefineV =diag((σkk))k=1....,r.

I Thus ifaj is the coefficient of thejth canonical variateUj, ajV−1/2 is the coefficient of the corresponding canonical variate Uj of the standardized variables.

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Results

I Let U= (U1, . . . , Ur) be the canonical variables for the first group with

U=AX1, where A= (p1,p2, . . . ,pr)

I Also let V= (V1, . . . , Vr)be the canonical variables for the second group with

V=BX2, where B= (q1,q2, . . . ,qr)

I Now Cov(U,X1) =Cov(AX1,X1) =AΣ11.

I Since V ar(Uj) = 1,

Corr(Uj, X1k) =Cov(Uj, X1k)/V ar(X1k).

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Results

I Let U= (U1, . . . , Ur) be the canonical variables for the first group with

U=AX1, where A= (p1,p2, . . . ,pr)

I Also let V= (V1, . . . , Vr)be the canonical variables for the second group with

V=BX2, where B= (q1,q2, . . . ,qr)

I Now Cov(U,X1) =Cov(AX1,X1) =AΣ11.

I Since V ar(Uj) = 1,

Corr(Uj, X1k) =Cov(Uj, X1k)/V ar(X1k).

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Results

I Let U= (U1, . . . , Ur) be the canonical variables for the first group with

U=AX1, where A= (p1,p2, . . . ,pr)

I Also let V= (V1, . . . , Vr)be the canonical variables for the second group with

V=BX2, where B= (q1,q2, . . . ,qr)

I Now Cov(U,X1) =Cov(AX1,X1) =AΣ11.

I Since V ar(Uj) = 1,

Corr(Uj, X1k) =Cov(Uj, X1k)/V ar(X1k).

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Results

I Let U= (U1, . . . , Ur) be the canonical variables for the first group with

U=AX1, where A= (p1,p2, . . . ,pr)

I Also let V= (V1, . . . , Vr)be the canonical variables for the second group with

V=BX2, where B= (q1,q2, . . . ,qr)

I Now Cov(U,X1) =Cov(AX1,X1) =AΣ11.

I Since V ar(Uj) = 1,

Corr(Uj, X1k) =Cov(Uj, X1k)/V ar(X1k).

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Results (contd.)

∴Corr(U,X1) =Cov(AX1, V11−1/2X1) =AΣ11V11−1/2.

I Summarizing,

Corr(U,X1) =AΣ11V11−1/2, Corr(V,X2) =BΣ22V22−1/2, Corr(U,X2) =AΣ12V22−1/2, Corr(V,X1) =BΣ21V11−1/2,

I These results give the relation between the canonical variables and the original variables.

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Results (contd.)

∴Corr(U,X1) =Cov(AX1, V11−1/2X1) =AΣ11V11−1/2.

I Summarizing,

Corr(U,X1) =AΣ11V11−1/2, Corr(V,X2) =BΣ22V22−1/2, Corr(U,X2) =AΣ12V22−1/2, Corr(V,X1) =BΣ21V11−1/2,

I These results give the relation between the canonical variables and the original variables.

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Special Cases

I We have r andsdimensional vectorsX1 andX2.

I Ifr =s= 1, i.e. one variable in each set (sayX1 andX2) then Corr(X1, X2) =√

λ1.

I Ifr >1 ands= 1, then for any j= 1, . . . , rand a0=ej, Corr(X1j, X2) = Corr(a00X1, X2)

≤ maxaCorr(a0X1, X2) =p λ1.

I In fact, observe that

maxaCorr(a0X1, X2) =p λ1

gives the multiple correlation ofX2 andX1 = (X11, . . . , X1r), i.e. the multiple correlation exceeds all simple correlations.

(21)

Special Cases

I We have r andsdimensional vectorsX1 andX2.

I Ifr =s= 1, i.e. one variable in each set (sayX1 andX2) then Corr(X1, X2) =√

λ1.

I Ifr >1 ands= 1, then for any j= 1, . . . , rand a0=ej, Corr(X1j, X2) = Corr(a00X1, X2)

≤ maxaCorr(a0X1, X2) =p λ1.

I In fact, observe that

maxaCorr(a0X1, X2) =p λ1

gives the multiple correlation ofX2 andX1 = (X11, . . . , X1r), i.e. the multiple correlation exceeds all simple correlations.

(22)

Special Cases

I We have r andsdimensional vectorsX1 andX2.

I Ifr =s= 1, i.e. one variable in each set (sayX1 andX2) then Corr(X1, X2) =√

λ1.

I Ifr >1 ands= 1, then for any j= 1, . . . , rand a0=ej, Corr(X1j, X2) = Corr(a00X1, X2)

≤ maxaCorr(a0X1, X2) =p λ1.

I In fact, observe that

maxaCorr(a0X1, X2) =p λ1

gives the multiple correlation ofX2 andX1 = (X11, . . . , X1r), i.e. the multiple correlation exceeds all simple correlations.

(23)

Special Cases

I We have r andsdimensional vectorsX1 andX2.

I Ifr =s= 1, i.e. one variable in each set (sayX1 andX2) then Corr(X1, X2) =√

λ1.

I Ifr >1 ands= 1, then for any j= 1, . . . , rand a0=ej, Corr(X1j, X2) = Corr(a00X1, X2)

≤ maxaCorr(a0X1, X2) =p λ1.

I In fact, observe that

maxaCorr(a0X1, X2) =p λ1

gives the multiple correlation ofX2 andX1 = (X11, . . . , X1r), i.e. the multiple correlation exceeds all simple correlations.

(24)

Special Cases

I In general, for anyr and s, with j= 1, . . . , rand k= 1, . . . , s andb0 =ek,

Corr(X1j, X2k) = Corr(a00X1,b00X2)

≤ maxa,bCorr(a0X1,b0X2) =p λ1.

I Observe that for any b0 =ek,

maxaCorr(a0X1,b00X2) ≤ maxa,bCorr(a0X1,b0X2) =p λ1. Since the left hand side gives the multiple correlation of X2 andX1= (X11, . . . , X1r), the first canonical correlation acts as an upper bound to all multiple correlations.

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Special Cases

I In general, for anyr and s, with j= 1, . . . , rand k= 1, . . . , s andb0 =ek,

Corr(X1j, X2k) = Corr(a00X1,b00X2)

≤ maxa,bCorr(a0X1,b0X2) =p λ1.

I Observe that for any b0 =ek,

maxaCorr(a0X1,b00X2) ≤ maxa,bCorr(a0X1,b0X2) =p λ1. Since the left hand side gives the multiple correlation of X2 andX1= (X11, . . . , X1r), the first canonical correlation acts as an upper bound to all multiple correlations.

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How to calculate canonical correlations

I To calculate the canonical correlations, suppose we have data (X1i,X2i), fori= 1, . . . , n i.e. we have a n×(r+s) order data matrix.

I DefineX= X1

X2

andS =

S11 S12

S21 S22

, whereXj = n1Pn

i=1Xji,j= 1,2 andSjk = 1nPn

i=1(Xji−Xj)0(Xki−Xk),j, k= 1,2.

I The method is then similar to the population canonical correlation, except that now we work withS instead ofΣ.

I The following Result follows as for the population canonical correlations.

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How to calculate canonical correlations

I To calculate the canonical correlations, suppose we have data (X1i,X2i), fori= 1, . . . , n i.e. we have a n×(r+s) order data matrix.

I DefineX= X1

X2

andS =

S11 S12

S21 S22

, whereXj = n1Pn

i=1Xji,j= 1,2 andSjk = 1nPn

i=1(Xji−Xj)0(Xki−Xk),j, k= 1,2.

I The method is then similar to the population canonical correlation, except that now we work withS instead ofΣ.

I The following Result follows as for the population canonical correlations.

(28)

How to calculate canonical correlations

I To calculate the canonical correlations, suppose we have data (X1i,X2i), fori= 1, . . . , n i.e. we have a n×(r+s) order data matrix.

I DefineX= X1

X2

andS =

S11 S12

S21 S22

, whereXj = n1Pn

i=1Xji,j= 1,2 andSjk = 1nPn

i=1(Xji−Xj)0(Xki−Xk),j, k= 1,2.

I The method is then similar to the population canonical correlation, except that now we work withS instead ofΣ.

I The following Result follows as for the population canonical correlations.

(29)

How to calculate canonical correlations

I To calculate the canonical correlations, suppose we have data (X1i,X2i), fori= 1, . . . , n i.e. we have a n×(r+s) order data matrix.

I DefineX= X1

X2

andS =

S11 S12

S21 S22

, whereXj = n1Pn

i=1Xji,j= 1,2 andSjk = 1nPn

i=1(Xji−Xj)0(Xki−Xk),j, k= 1,2.

I The method is then similar to the population canonical correlation, except that now we work withS instead ofΣ.

I The following Result follows as for the population canonical correlations.

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Result

I Let ˆλ1 ≥λˆ2≥. . .≥ˆλr be the eigenvalues of

S11−1/2S12S22−1S21S11−1/2 andpˆ1,pˆ2, . . . ,pˆr the corresponding eigen-vectors.

I In fact, ˆλ1 ≥λˆ2≥. . .≥ˆλr are also the r largest eigen-values of S22−1/2S21S11−1S12S22−1/2 withqˆ1,qˆ2, . . . ,qˆr the

corresponding eigen-vectors.

Result

Thus for any unit(X1k,X2k), thejth sample canonical variate pair isUˆ1 = ˆp01S11−1/2X1k andVˆ2 = ˆq01S22−1/2X2k with

Corr( ˆU1,Vˆ1) = ˆρj = qλˆj.

(31)

Result

I Let ˆλ1 ≥λˆ2≥. . .≥ˆλr be the eigenvalues of

S11−1/2S12S22−1S21S11−1/2 andpˆ1,pˆ2, . . . ,pˆr the corresponding eigen-vectors.

I In fact, ˆλ1 ≥λˆ2≥. . .≥ˆλr are also the r largest eigen-values of S22−1/2S21S11−1S12S22−1/2 withqˆ1,qˆ2, . . . ,qˆr the

corresponding eigen-vectors.

Result

Thus for any unit(X1k,X2k), thejth sample canonical variate pair isUˆ1 = ˆp01S11−1/2X1k andVˆ2 = ˆq01S22−1/2X2k with

Corr( ˆU1,Vˆ1) = ˆρj = qλˆj.

(32)

Result

I Let ˆλ1 ≥λˆ2≥. . .≥ˆλr be the eigenvalues of

S11−1/2S12S22−1S21S11−1/2 andpˆ1,pˆ2, . . . ,pˆr the corresponding eigen-vectors.

I In fact, ˆλ1 ≥λˆ2≥. . .≥ˆλr are also the r largest eigen-values of S22−1/2S21S11−1S12S22−1/2 withqˆ1,qˆ2, . . . ,qˆr the

corresponding eigen-vectors.

Result

Thus for any unit(X1k,X2k), thejth sample canonical variate pair isUˆ1 = ˆp01S11−1/2X1k andVˆ2 = ˆq01S22−1/2X2k with

Corr( ˆU1,Vˆ1) = ˆρj = qλˆj.

(33)

Example

I The following problem (Johnson-Wichern, 2009) seeks to study the relationship between 5 job characteristics and7job satisfaction variables, i.e. r = 5 ands= 7.

I The data is based on interviews of 784executives.

I The following is the correlation matrix :

1.00 0.49 0.53 049 0.51 0.33 0.32 0.20 0.19 0.30 0.37 0.21 0.49 1.00 0.57 0.46 0.53 0.30 0.21 0.16 0.08 0.27 0.35 0.20 0.53 0.57 1.00 0.48 0.57 0.31 0.23 0.14 0.07 0.24 0.37 0.18 0.49 0.46 0.48 1.00 0.57 0.24 0.22 0.12 0.1‘9 0.21 0.29 0.26 0.51 0.53 0.57 0.57 1.00 0.38 0.32 0.17 0.23 0.32 0.36 0.27 0.33 0.30 0.31 0.24 0.38 1.00 0.43 0.27 0.24 0.34 0.37 0.40 0.32 0.21 0.23 0.22 0.32 0.43 1.00 0.33 0.26 0.54 0.32 0.58 0.20 0.16 0.14 0.12 0.17 0.27 0.33 1.00 0.25 0.46 0.29 0.45 0.19 0.08 0.07 0.19 0.23 0.24 0.26 0.25 1.00 0.28 0.30 0.27 0.30 0.27 0.24 0.21 0.32 0.34 0.52 0.46 0.28 1.00 0.35 0.59 0.37 0.35 0.37 0.29 0.36 0.37 0.32 0.29 0.30 0.35 1.00 0.31 0.21 0.20 0.18 0.26 0.27 0.40 0.58 0.45 0.27 0.59 0.31 1.00

(34)

Example

I The following problem (Johnson-Wichern, 2009) seeks to study the relationship between 5 job characteristics and7job satisfaction variables, i.e. r = 5 ands= 7.

I The data is based on interviews of 784executives.

I The following is the correlation matrix :

1.00 0.49 0.53 049 0.51 0.33 0.32 0.20 0.19 0.30 0.37 0.21 0.49 1.00 0.57 0.46 0.53 0.30 0.21 0.16 0.08 0.27 0.35 0.20 0.53 0.57 1.00 0.48 0.57 0.31 0.23 0.14 0.07 0.24 0.37 0.18 0.49 0.46 0.48 1.00 0.57 0.24 0.22 0.12 0.1‘9 0.21 0.29 0.26 0.51 0.53 0.57 0.57 1.00 0.38 0.32 0.17 0.23 0.32 0.36 0.27 0.33 0.30 0.31 0.24 0.38 1.00 0.43 0.27 0.24 0.34 0.37 0.40 0.32 0.21 0.23 0.22 0.32 0.43 1.00 0.33 0.26 0.54 0.32 0.58 0.20 0.16 0.14 0.12 0.17 0.27 0.33 1.00 0.25 0.46 0.29 0.45 0.19 0.08 0.07 0.19 0.23 0.24 0.26 0.25 1.00 0.28 0.30 0.27 0.30 0.27 0.24 0.21 0.32 0.34 0.52 0.46 0.28 1.00 0.35 0.59 0.37 0.35 0.37 0.29 0.36 0.37 0.32 0.29 0.30 0.35 1.00 0.31 0.21 0.20 0.18 0.26 0.27 0.40 0.58 0.45 0.27 0.59 0.31 1.00

(35)

Example

I The following problem (Johnson-Wichern, 2009) seeks to study the relationship between 5 job characteristics and7job satisfaction variables, i.e. r = 5 ands= 7.

I The data is based on interviews of 784executives.

I The following is the correlation matrix :

1.00 0.49 0.53 049 0.51 0.33 0.32 0.20 0.19 0.30 0.37 0.21 0.49 1.00 0.57 0.46 0.53 0.30 0.21 0.16 0.08 0.27 0.35 0.20 0.53 0.57 1.00 0.48 0.57 0.31 0.23 0.14 0.07 0.24 0.37 0.18 0.49 0.46 0.48 1.00 0.57 0.24 0.22 0.12 0.1‘9 0.21 0.29 0.26 0.51 0.53 0.57 0.57 1.00 0.38 0.32 0.17 0.23 0.32 0.36 0.27 0.33 0.30 0.31 0.24 0.38 1.00 0.43 0.27 0.24 0.34 0.37 0.40 0.32 0.21 0.23 0.22 0.32 0.43 1.00 0.33 0.26 0.54 0.32 0.58 0.20 0.16 0.14 0.12 0.17 0.27 0.33 1.00 0.25 0.46 0.29 0.45 0.19 0.08 0.07 0.19 0.23 0.24 0.26 0.25 1.00 0.28 0.30 0.27 0.30 0.27 0.24 0.21 0.32 0.34 0.52 0.46 0.28 1.00 0.35 0.59 0.37 0.35 0.37 0.29 0.36 0.37 0.32 0.29 0.30 0.35 1.00 0.31 0.21 0.20 0.18 0.26 0.27 0.40 0.58 0.45 0.27 0.59 0.31 1.00

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Example (contd.)

I The correlation matrix of the 12 variables imply that we need to look at 35 correlations (the largest being0.59) to

understand the relationship between the two sets. This is difficult to interpret.

I Instead do a canonical correlation.

I The first canonical variables are

1 = 0.42X11+ 0.21X12+ 0.17X13−0.02X14+ 0.44X15

1 = 0.42X21+ 0.22X22−0.03X23+ 0.01X24+ 0.29X25

+0.52X26−0.12X27 with Corr( ˆU1,Vˆ1) = 0.55.

I The 1st canonical correlation coefficient shows that there is reasonable relationship between the two groups.

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Example (contd.)

I The correlation matrix of the 12 variables imply that we need to look at 35 correlations (the largest being0.59) to

understand the relationship between the two sets. This is difficult to interpret.

I Instead do a canonical correlation.

I The first canonical variables are

1 = 0.42X11+ 0.21X12+ 0.17X13−0.02X14+ 0.44X15

1 = 0.42X21+ 0.22X22−0.03X23+ 0.01X24+ 0.29X25

+0.52X26−0.12X27 with Corr( ˆU1,Vˆ1) = 0.55.

I The 1st canonical correlation coefficient shows that there is reasonable relationship between the two groups.

(38)

Example (contd.)

I The correlation matrix of the 12 variables imply that we need to look at 35 correlations (the largest being0.59) to

understand the relationship between the two sets. This is difficult to interpret.

I Instead do a canonical correlation.

I The first canonical variables are

1 = 0.42X11+ 0.21X12+ 0.17X13−0.02X14+ 0.44X15

1 = 0.42X21+ 0.22X22−0.03X23+ 0.01X24+ 0.29X25

+0.52X26−0.12X27 with Corr( ˆU1,Vˆ1) = 0.55.

I The 1st canonical correlation coefficient shows that there is reasonable relationship between the two groups.

(39)

Example (contd.)

I The correlation matrix of the 12 variables imply that we need to look at 35 correlations (the largest being0.59) to

understand the relationship between the two sets. This is difficult to interpret.

I Instead do a canonical correlation.

I The first canonical variables are

1 = 0.42X11+ 0.21X12+ 0.17X13−0.02X14+ 0.44X15

1 = 0.42X21+ 0.22X22−0.03X23+ 0.01X24+ 0.29X25

+0.52X26−0.12X27 with Corr( ˆU1,Vˆ1) = 0.55.

I The 1st canonical correlation coefficient shows that there is reasonable relationship between the two groups.

(40)

Advantages of canonical correlations

I Firstly it reduces the number of correlations coefficients to be studied from rsto 1 or2. Particularly, convenient when r and sare large.

I Secondly, if the canonical correlations are high, then we can work with one group only instead of both (usually the smaller), i.e. it can act as a dimension reduction technique.

(41)

Advantages of canonical correlations

I Firstly it reduces the number of correlations coefficients to be studied from rsto 1 or2. Particularly, convenient when r and sare large.

I Secondly, if the canonical correlations are high, then we can work with one group only instead of both (usually the smaller), i.e. it can act as a dimension reduction technique.

(42)

Summary

I The canonical correlation of standardized variables is discussed.

I Results relating the original and canonical variables are derived.

I Some special cases are listed.

I A numerical illustration is given.

(43)

Summary

I The canonical correlation of standardized variables is discussed.

I Results relating the original and canonical variables are derived.

I Some special cases are listed.

I A numerical illustration is given.

(44)

Summary

I The canonical correlation of standardized variables is discussed.

I Results relating the original and canonical variables are derived.

I Some special cases are listed.

I A numerical illustration is given.

(45)

Summary

I The canonical correlation of standardized variables is discussed.

I Results relating the original and canonical variables are derived.

I Some special cases are listed.

I A numerical illustration is given.

References

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