1Stat-Math Unit, Indian Statistical Institute, 203 B.
T. Rd., Calcutta 700108, India
2Department of Mathematics, Indian Institute of Science, Bangalore 560012, India
rudra@isical.ac.in veluma@math.iisc.ernet.in
Mathematics Subject Classification 2000: 43A80, 22E
Keywords:Wiener Tauberian Theorem, Heisenberg Motion group.
REVIEWS
An analogue of the Wiener Tauberian Theorem for the Heisenberg Motion group
Rudra P Sarkar
1AND Sundaram Thangavelu
2Abstract|We show that the Wiener Tauberian property holds for the Heisenberg Motion groupTnB<Hn. This is a special case of the same result for a wider class of groups. However, our exposition is almost self contained and the techniques used in the proof are relatively simple.
1. Introduction
A locally compact group is said to have Wiener’s property if every two sided ideal in the Banach
∗algebraL1(G)is contained in the kernel of a nondegenerate Banach∗representation ofL1(G) on a Hilbert space. It is well known from the work of Leptin [7] that semidirect product of abelian groups and connected nilpotent groups have the Wiener’s property. On the other hand it was established by M. Duflo that no semisimple Lie group has this property [7].
IfGis compact extension of a nilpotent group then it it is of polynomial growth [4] andGhas a symmetric group algebra. These two properties together imply thatGhas Wiener’s property [8]. For the case of general locally compact motion groups see the work of Gangolli [3].
We consider one such groupG=TnB<Hn, the semidirect product of then-dimensional torus Tnand 2n+1 dimensioanl Heisenberg groupHn. The above theory points out that it has Wiener’s property. However this far reaching general theory related to the groups of polynomial growth involves heavy machinary and hence not easily accessible.
We offer here a direct and independent proof of the fact forGas above, starting from a result of Hulanicki and Ricci [5]. We interpret the result in [5] onHnas a Wiener’s theorem forTn-biinvariant functions on G. Using elementary arguments
we extend this result to a Wiener’s theorem for the full group G. Going towards the proof we find the representations in bG and establish the Plancherel theorem. Then we obtain the Wiener’s theorem explicitly in terms of the representations.
Precisely, we find the sufficient condition that an L1-function onGgenerates a dense ideal inL1(G).
This condition is also necessary. We may conjecture that this method of extending the theorem from the biinvariant functions inL1(G)to the fullL1(G) would work for other compact extensions.
This exposition is almost self contained and techniques are simple. Our groupGis a subgroup of the so called Heisenberg Motion group, which is the semidirect product of the Heisenberg group Hnand the unitary groupU(n). This latter group acts onHnas automorphisms and the semidirect productU(n)B<Hnturns out to be the natural group of isometries for the Heisenberg geometry;
see the works of Koranyi [6] and Strichartz [10]. In [9] R. Rawat has studied a Wiener’s theorem for the action ofU(n)B<HnonHn.
2. Notation and Preliminaries LetHn=Cn×R, with group law
(z,t)◦(z0,t0)=
z+z0,t+t0−1 2I m z0.z
,
denote the (2n+1)-dimensional Heisenberg group. LetTn=S1× ··· ×S1(ntimes) be then- dimensioanl Torus. The groupTnacts naturally onHnby automorphisms and(Hn,Tn)forms a Gelfand pair. LetG=TnB<Hnbe the semidirect product ofHnandTn. Let us denote the elements ofGby(σ,z,t)whereσ=(eiθ1,...,eiθn)∈Tnand (z,t)∈Hn. The group law ofGis given by:
(σ,z,t).(τ,w,s)
=
στ,z+σw,t+s−1
2I mσw.¯z
. AsTnis a subgroup ofGthrough the identification ofσand(σ,0,0), it acts onGfrom left and right through the group law as:
(σ,0,0).(τ,w,s)=(στ,σw,s) and
(τ,w,s).(σ,0,0)=(στ,w,s).
The Heisenberg group Hn can also be identified naturally both as a subgroup of G and as the quotient G/Tn. For an element (σ,z,t)∈G, (σ,z,t)−1=(σ−1,−σ−1z,−t)= (σ−1,0,0)(1,−z,−t).
We use Rn+ for R+× ··· ×R+ (n times) where R+ is the set of positive reals. The n- dimesional Euclidean space is denoted by Rn. For this article ‘.’ is the usual bilinear inner product. For2=(θ1,...θn)∈ [0,2π)nwe denote (eiθ1, ... ,eiθn)∈Tn by ei2. A function f on Hnis calledpolyradialiff(z,t)=f(ei2z,t)for all ei2∈Tn, where z=(z1, ... ,zn)∈Cn and ei2z=(eiθ1z1,...,eiθnzn). We considerC∞c (G)to be the space of compactly supportedC∞-functions.
For a functionf∈Cc∞(G)we define a function f0 onHnbyf0(z,t)=f(1,z,t)and a polyradial functionf00onHnbyf00(r,t)=f(1,r,t), where r=(r1,...,rn),rj≥0. Forµ=(µ1,...,µn)∈Zn the characterχµ ofTn is defined byχµ(ei2)= eµ.2=eiµ1θ1.···.eiµnθn. Suppose µ,µ0∈Zn. A complex valued functionf onGis called spherical of right (resp. left) typeµ(resp.µ0) if
f(xk1) = f(x)χµ(k1) (resp.f(k2x)
= χµ0(k2)f(x))
for allx∈G and k1,k2∈Tn. A function of left typeµ0and right typeµis called spherical of type (µ0,µ). For a functionf∈C∞c (G)
Z
Tnχµ(k1)f(xk1)dk1 and Z
Tnχµ0(k2)f(k2x)dk2
respectively are its projections on the space of right µ and left µ0 type functions in C∞c (G). For a suitable function space S , by Sµ0,µ we denote the projection of S on the subspace of left µ0 and right µtype functions ofS. The polyradial functions inL1(Hn)(denoted byAin [5]) is under obvious identification the same asL1(G)0,0, the bi- Tninvariant functions inL1(G). The right and left G-translates off forx∈G, are denoted respectively by fx and xf. Precisely, fx(y)=f(yx−1) and
xf(y)=f(x−1y). By∗we mean convolution in Gwhile∗Hndenotes the convolution inHn. For two elementsm,n∈Rn,m−nis the component- wise subtraction. Bym>nwe meanmj>njfor everyj=1,...,n.
We conclude this section with the following proposition.
Proposition 2.1. Let f,g∈C∞c (G). Then, (i) left type off∗gis the left type off and the right
type of f∗g is right type of g.
(ii) if moreoverf andgare of rightm-type and left n-type respectively, then,f∗g≡0ifm6=nand if m=n then f∗g(1,z,t)=f0∗Hng0(z,t) Proof of this proposition follows easily considering the fact that every elementg∈Gcan be decomposed asg=xk=k1x1wherex,x1∈Hnandk,k1∈Tn. By (i) aboveL1(G)µ,µ is a subalgebra ofL1(G) under convolution∗.
3. Representations ofG
We shall construct the representations ofGfrom that ofHnand the Euclidean motion groupM(2). For details of the representations of these two groups we refer to [12] and [11] respectively.
For k=0,1,2, ... , and t∈R the Hermite polynomials are defined by
Hk(t)=(−1)k dk
dtk{e−t2}et2
! .
The normalized Hermite functions are defined in terms of the Hermite polynomials as
hk(t)=(2k√
πk!)−12Hk(t)e−12t2. These Hermite functions{hk:k=0,1,2,...}form an orthonormal basis ofL2(R). For any multiindex αand x∈Rnwe define the higher dimensional Hermite functions8αby taking tensor product:
8α(x)=5nj=0hαj(xj).
Then the family{8α}is an orthonormal basis of L2(Rn). Forl6=0 we define thescaledHermite functions
8lα(x)= |l|n48α
|l|12x .
We also consider
8lαβ(x)=(2π)−n2|l|n2hπl(z,0)8lα,8lβi, which is essentially the matrix coefficient of the Schr¨odinger representation πl at (z,0) of Hn. They are the so called special Hermite functions and{8lαβ :α,β∈Nn}is a complete orthonormal system inL2(Cn). For eachσ∈Tn,(z,t)7→(σz,t) is an automorphism ofHn, becauseTnpreserves the symplectic formI m(z.w). Ifρis a representation ofHn, then using this automorphism we can define another representationρσbyρσ(z,t)=ρ(σz,t) which coincides withρ at the center. Therefore by Stone-von Neumann theoremρσis unitarily equivalent toρ. If we takeρto be the Schr¨odinger representation πl, then we have the unitary intertwining operatorµl(σ), i.e.
πl(σz,t)=µl(σ)πl(z,t)µl(σ)∗. The operator valued functionµl can be chosen so that it becomes a unitary representation of the double cover of the symplectic group and is called metaplectic representation. For a detailed description of these representations we refer to [2].
For each l6=0,m∈ Zn we consider the representations(ρlm,L2(Rn))defined by
ρlm(ei8,z,t)=e−im.8πl(z,t)µl(ei8), whereµl(ei8)is the metaplectic representation andπl is the Schr¨odinger representation ofHn. The action of µl(ei8) on the Hermite basis {8lα:α∈Nn}is given by
µl(ei8)8lα=eiα.88lα.
Sinceρlm(1,z,t)=πl(z,t), these representations are irreducible.
Theorem 3.1. Letπbe any unitary representation of Gsuch thatπ(1,z,t)is irreducible as a representation of Hn. If π(1,0,t)=eiltI with l6=0 then π is unitarily equivalent toρlmfor some m∈Zn. Proof.Sinceπ(1,z,t)is irreducible andπ(1,0,t)= eiltIby Stone-von Neumann theoremπis unitarily equivalent toπl(z,t)onL2(Rn). IfHis the Hilbert
space on which πis realised, we have a unitary operatorUl:H−→L2(Rn)such that
Ul∗πl(z,t)Ul=π(1,z,t).
Now
π(ei8,z,t)=π(1,z,t)π(ei8,0,0) and also
π(ei8,z,t) = π((ei8,0,0)(1,e−i8z,t))
= π(ei8,0,0)π(1,e−i8z,t).
Therefore,
Ulπ(1,z,t)π(ei8,0,0)Ul∗
=Ulπ(ei8,0,0)π(1,e−i8z,t)Ul∗ and
πl(z,t)Ulπ(ei8,0,0)Ul∗
=Ulπ(ei8,0,0)Ul∗πl(e−i8z,t).
But πl(e−i8z,t) is unitarily equivalent to πl(z,t)via the metaplectic representation, i.e.
πl(e−i8z,t)=µl(e−i8)πl(z,t)µ(e−i8)∗. Definingρ(ei8)=Ulπ(ei8,0,0)Ul∗we have
πl(z,t)ρ(ei8)
=ρ(ei8)µ(e−i8)π(z,t)µl(e−i8)∗. Thus ρ(ei8)µ(e−i8) commutes with πl(z,t) for all (z,t) and hence ρ(ei8)µl(e−i8)= χ(8)I. That isρ(ei8)=χ(8)µl(ei8). Therefore χ(8).χ(80)=χ(8+80). Thus χ defines a character of the group Tn. Hence, ρ(ei8)= e−im.8µ(ei8)for somem∈Zn. Finally
Ulπ(ei8,z,t)Ul∗=πl(z,t)e−im.8µ(ei8) which proves the theorem.
We now consider the case whenl=0. That is π(ei8,z,t)=π(ei8,z,0).
Definingρ(z,ei8)=π(ei8,z,0)we see that ρ(z,ei8)ρ(w,ei2) = π(ei8,z,0)π(ei2,w,0)
= π(ei(2+8),z+ei8w,0) and henceρis a representation of the motion group Cn×Tn=M(2)× ··· ×M(2)whereM(2)=C× U(1).
It is well known (see [11]) that all the irreducible unitary representations ofM(2)are given by the following two families
(i) fora>0,ρarealised onL2(T)and defined by ρa(z,eiφ)g(θ)=eiRe(aze−iθ)g(θ−φ).
(ii) for m ∈ Z, the one-dimensional representationsχmrealised onCand defined by
χm(eiφ)z=eimφz.
From this we build the representations ofM(2)×
··· ×M(2)as:
(I) for a=(a1, ...an)∈Rn+, ρa realised on L2(Tn)is given by
ρa(z,ei8)g(ei2) = 5nj=1eiRe(ajzje
−iθj)
×g(ei(2−8)), wherez=(z1,...zn)∈Cn,ei2∈Tn. (II) form∈Zn,χmrealised onCis given by
χm(ei8)w=eim.8w. Hence we have,
Theorem 3.2. Ifπis a unitary representation ofG such thatπ(1,0,t)=Iandπ(1,z,t)is irreducible thenπis unitarily equivalent to eitherρafor some a∈Rn+orχmfor some m∈Zn.
We now show that the representations ρlm are enough for the Plancherel theorem. Givenf∈L1∩ L2(G)consider the group Fourier transform
bf(l,m) = Z
f(ei8,z,t)ρlm(ei8,z,t)d8dzdt
= Z
fl(ei8,z)e−im.8πl(z,0)µl(ei8)
×d8dz where fl(ei8,z)=R
eiltf(ei8,z,t)dt. We can calculate the Hilbert–Schmidt operator norm of bf(l,m)by using the Hermite basis{8lα}:
bf(l,m)8lα = Z
fl(ei8,z)e−im.8eiα.8πl
×(z,0)8lαd8dz
= Z
f˜l(m−α,z)πl(z,0)8lαdz where
f˜l(z,m)= Z
fl(z,ei8)e−im.8d8.
Thus
(bf(l,m)8lα,8lβ)
=(2π)n2|l|−n2 Z
f˜l(z,m−α)8lαβ(z)dz so that
kbf(l,m)8lαk22
=(2π)n|l|−nX
β
| Z
f˜l(z,m−α)8lαβ(z)dz|2
and
kbf(l,m)k2H S = (2π)n|l|−n
×X
α
X
β
Z
f˜l×(z,m−α)8lαβ(z)dz
2.
This shows that X
m
kbf(l,m)k2H S=(2π)n|l|−n
×X
m
X
α
X
β
Z
f˜l(z,m−α)8lαβ(z)dz|2.
Making a change of variable in the summation over mand noting that{8lαβ:α,β∈Nn}is an orthonormal basis forL2(Cn)we obtain
X
m
kbf(l,m)k2H S
=(2π)n|l|−nX
m
Z
| ˜fl(z,m)|2dz
=(2π)2n|l|−n Z Z
|fl(ei8,z)|2d8dz. Therefore,
Z X
m
kbf(l,m)k2H S
!
|l|ndl
=(2π)2nZ Z Z
|fl(ei8,z)|2d8dz
=(2π)2n+1Z
|f(ei8,z,t)|2d8dzdt. Theorem 3.3. (Plancherel)For f∈L1∩L2(G)
Z
|f(ei8,z,t)|2d8dzdt
=(2π)−2n−1Z ∞
−∞
X
m
kbf(l,m)k2
!
|l|ndl.
Remark 3.4. Note that if f(ei8z,t)is right Tn- invariant then(bf(l,m)8lα,8lβ)=0 unless m= α≥0. Thusbf(l,m)=0 formj<0 for somejand form≥0
kbf(l,m)k2H S
=(2π)n|l|−nX
β∈Zn
bf(l,m)8lm,8lβ
2.
We also use the notationρlm(f)forbf(l,m).
4. Wiener’s Theorem
We begin with a theorem of Hulanicki and Ricci [5]
Theorem 4.1. Let J be a proper closed ideal of L1(Hn/Tn). Suppose for every non-zero multiplicative functional3ψofL1(Hn/Tn), given by the bounded spherical function ψ, there is a function f∈J such that
3ψ(f)= Z
f(z,t)ψ(z,t)dzdt6=0.
Then J=L1(Hn/Tn).
The actual Theorem of Hulanicki and Ricci is little stronger than this as it says thatL1(Hn)∗HnJ is dense inL1(Hn). We have quoted the part which we are going to use. A detailed proof of this can be found in [1]. Note that in our notationL1(Hn/Tn) isL1(G)0,0. In the language of representations this theorem can be restated as: forJas above, suppose (i) for every (l,m)∈R\ {0} ×Zn there is a
functionfl,m∈Jsuch thatρlm(fl,m)6=0 (ii) for everya=(a1,...,an)withai>0 there is
afa∈Jsuch thatρa(fa)6=0 (iii) there isf ∈Jsuch thatR
Hnf dzdt6=0.
ThenJ=L1(G)0,0. Forz=(z1,...,zn)∈Cnwe consider itsmulti-polardecomposition
z=ei2kzk =(r1eiθ1,...,rneiθn), whereei2∈Tn,kzk =(r1,...,rn)andzj=rjeiθj forj=1,...,n. Notice that condition (ii) is then equivalent to this: the Euclidean Fourier transform of fa at a∈Rn+ is not equal to zero. That is bfa(.,t)(a)6=0.
Proposition 4.2. Letf ∈L1(G). If right(resp. left) type off isµ(resp.µ0)thenbf(l,m)≡0ifmj<µj
(resp. mj0 <µj0) for some j,j0. For f ∈L1(G) of type (µ0,µ), hρlm(f)8lα, 8lβi 6=0 only when µj=mj−αjandµ0j=mj−βjfor all j.
Proof.
hρlm(f)8lα,8lβi
= Z
G
f(ei2,z,t)h8lα,ρlm
×(ei2,z,t)−18lβid2dzdt
= Z
G
f(ei2,z,t)h8lα,ρlm
×(e−i2,−e−i2z,−t)8lβid2dzdt
= Z
G
f(ei2,ei2e−i2z,t)h8lα,e−i(β−m)2πl
×(−e−i2z,−t)8lβid2dzdt
= Z
G
eiµ0.2f(1,e−i2z,t)ei(β−m)2
×h8lα,πl(−e−i2z,−t)8lβid2dzdt. Therefore,hρlm(f)8lα,8lβi =0 unlessµ0=m− βin which case,
hρlm(f)8lα,8lβi
= Z
Hn
f(1,z,t)h8lα,πl(−z,−t)8lβidzdt. The other result will follow similarly.
Lemma 4.3. Suppose forf ∈L1(G),bf(l,m)6=0for somel∈R\ {0},m∈Znandρa(f)6=0for some a∈Rn+. Assume also thatµ∈Znsatisfiesµ≤m.
Then there exist functionsgandg0of type(µ,µ)in the closure of span of(left and right)G-translates of f such thatbg(l,m)6=0andρa(g0)6=0.
Proof.Letν=m−µ. As the operatorbf(l,m)6=0 there existαandβsuch thathbf(l,m)8lα,8lβi 6=0.
Sinceρlmis irreducible, for everyε >0 there exist ci∈Candxi∈G,i=1,2,...,sfor somessuch that
s
X
i=1
ciρlm(xi)8lν−8lα <ε.
This implies
s
X
i=1
ciρlm(f)ρlm(xi)8lν−ρlm(f)8lα
<εkρlm(f)k and hence
ρlm(g1)8lν−ρlm(f)8lα
<εkρlm(f)k whereg1=Ps
i=1cifxi.
As ρlm(f)8lα 6= 0 and kρlm(f)k < ∞, ρlm(g1)8lν 6=0. By the above proposition this also shows that g1 has right µ component. Let g2 be the right µ-th projection of g1. Then ρlm(g1)8lν =ρlm(g2)8lν 6=0, because Fourier transforms of other right projections ofg1will kill 8lν. There existsγsuch thathρlm(g2)8lν,8lγi 6=0.
Forε >0, there arecj0∈Candyj∈G,j=1,2,...s0 for somes0such that
s0
X
j=1
cj0ρlm(y−1j )8lν−8lγ <ε.
Applyingρlm(g2)∗on both sides and using thatρlm is unitary we get,
s0
X
j=1
c0jρlm(g2)∗ρlm(yj)∗8lν
−ρlm(g2)∗8lγ
<εkρlm(g2)∗k. That implies
s0
X
j=1
c0jρlm(yjg2)∗8lν−ρlm(g2)∗8lγ
<εkρlm(g2)∗k.
Letg3=Ps0
j=1c0j yjg2. Then we have
kρlm(g3)∗8lν−ρlm(g2)∗8lγk<εkρlm(g2)∗k. Asρlm(g2)∗8lγ6=0,ρlm(g3)∗8lν6=0. Sinceg3is a finite linear combination of the leftG-translates ofg2, right type ofg3 continues to beµ. Hence h8lν,ρlm(g3)∗8lνi = hρlm(g3)8lν,8lνi 6=0. Letgbe the leftµ-th projection ofg3. Theng is of type (µ,µ)andhρlm(g3)8lν,8lνi 6=0.
By similar method we can show that there is ag0of type(µ,µ)in the closure of the span of G-translates off such thatρa(g0)6=0.
Suppose f is a function in L1(G)µ,µ. Let z=ei2kzkwherekzk =(r1,...,rn)andei2∈Tn. Then
f(ei8,z,t) = f(ei8,ei2kzk,t)
= eiµ.8f(1,ei2kzk,t).
Since(1,ei2kzk,t)=(ei2,0,0)(e−i2,kzk,t)we also have
f(1,ei2kzk,t) = eiµ.2f(e−i2,kzk,t)
= f(1,kzk,t).
Thus we have
f(ei8,z,t)=eiµ8f00(kzk,t).
By the above proposition for f ∈L1(G)µ,µ, ρlm(f)=0 whenevermj<µjfor somej. Ifm≥µ then
ρlm(f) = Z
G
f(ei8,z,t)ρlm(ei8,z,t)d8dzdt
= Z
G
f00(kzk,t)eiµ.8e−im.8πl(z,t)µl
×(ei8)d8dzdt
= Z
G
f00(kzk,t)ρlm−µ(ei8,z,t)d8dzdt. This shows thatρlm(f)=ρlm−µ(f00).
Now suppose for somef ∈L1(G) χm(f)=
Z
G
f(ei8,z,t)e−im.8dzdt d86=0. Letfµis the rightµ-th projection off. That is
fµ(ei8,z,t) = Z
G
f(ei(2+8),z,t)e−iµ.2d2
= eiµ.8 Z
G
f(ei2,z,t)e−iµ2d2.
Then
χm(fµ) = δm,µ
Z
G
f(ei2,z,t)e−iµ.2d2dzdt
= δm,µχµ(f)
where δm,µ is the Kronecker δ and hence if µ=mthen χµ(fµ)6=0. Similarly we can show that if µf is the left µ-th projection of f, then χm(µf)=δm,µχµ(f). Therefore ifχm(f)6=0 for allm∈Zn, thenχµ(g)6=0 wheregis the(µ,µ)- the projectionf. By the above computation that meansR
Hng0,0(kzk,t)dzdt6=0.
Proposition 4.4. Let S⊂L1(G)µ,µSuppose (1) for everyl∈R\ {0}andm≥µ, there isfl,m∈S
such thatρlm(fl,m)6=0,
(2) for all a∈R+n,ρa(fa)6=0for some function fa∈S and
(3) χµ(f)6=0for some function f∈S.
Then the span of the ideal(under convolution∗) generated by elements ofSinL1(G)µ,µis dense in L1(G)µ,µ.
Proof.LetS0,0= {f0,0:f∈S}. Iff∈L1(G)µ,µ, then ρlm(f)6=0 for somem≥µimpliesρlm−µ(f0,0)6=0.
Also ρa(f)6=0 implies the Euclidean Fourier transform bf0,0(.,t)(a)6=0. Notice also that χµ(f) 6= 0 implies R
Hnf0,0(kzk,t)dzdt 6=0.
Therefore by Theorem 4.1 span of the ideal generated by the elements of S0,0 in L1(G)0,0 is dense in L1(G)0,0. Let us take an arbitrary h∈L1(G)µ,µ. Forε >0, there existcj∈C,fj∈S andgj∈L1(G)0,0,j=1,2,...sfor somessuch that
X
j
cjf0,0j ∗Hngj−h0,0
L1(Hn)<ε. (4.1)
Let us define ˜
gj(ei2,z,t)=gj(kzk,t)eiµ.2. Clearly g˜j∈L1(G)µ,µ. Then,
Xcjfj∗ ˜gj−h L1(G)
= Z
G
Xcjfj∗ ˜gj(ei2,z,t)−h(ei2,z,t)
×d2dzdt.
Sincefj∗ ˜gjandhare functions of type(µ,µ), the above expression equals to
Z
G
Xcj(fj∗ ˜gj))0,0(kzk,t)eiµ.2
−h0,0(kzk,t)eiµ.θ|d2dzdt
= Z
Hn
Xcj(fj∗ ˜gj))0,0(kzk,t)
−h0,0(kzk,t)|dzdt.
Again using the fact thatfj∗ ˜gjandhare(µ,µ)- functions we have
(fj∗ ˜gj)0,0(kzk,t) = fj∗ ˜gj(1,z,t)
= (f0j∗Hn ˜
gj0)(kzk,t) by Proposition 2.1. Also,
g˜j0(z,t)= ˜gj(1,z,t)=gj(kzk,t)=gj(z,t) and
f0j(z,t)=fj(1,z,t)=f0j,0(kzk,t)=f0j,0(z,t).
Therefore,
(fj∗ ˜gj)0,0(kzk,t)=f0,0j ∗Hngj(z,t).
Hence
Xcjfj∗ ˜gj−h L1(G)
= Z
Hn
Xcj(f0j,0∗Hng˜j)(kzk,t)
−h0,0(kzk,t)|dzdt.
The proposition follows now from (4.1).
We now state and prove a Wiener Tauberian theorem for the action ofGon itself.
Theorem 4.5. If for a functionf ∈L1(G),bf(l,m) 6=0for alll6=0,m∈Zn,bf(a)6=0for alla∈Rn+
andχm(f)6=0for allm∈Znthen the span of the (left and right)G-translates off is dense inL1(Gx).
Proof. Fix µ∈Zn. From lemma 4.3 and the subsequent computations we see that using the given nonvanishing condition onf, we can find functions of type(µ,µ)in the closure ofG-translates off such that they satisfy the hypothesis of proposition 4.4. Hence they can generateL1(G)µ,µ. The proof now follows from the fact that any idealIinL1(G) which containsL1(G)µ,µfor allµ∈ZnisL1(G) itself.
Note that instead of a single functionf we can also take a subset S⊂L1(G) such that Fourier transforms of the elements ofShave no common zero in the set of above representations parametrized by R∗×Zn∪R+n ∪Zn, where R∗ is the set of nonzero reals.
Received 18 September 2007; revised 03 December 2007.
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Rudra Sarkarreceived his Ph.D from Indian Statistical Institute in 1998.
After straying into computer industry for almost five years he returned to Mathematics in 2000. Currently he is an Assistant professor with the Statistics and Mathematics division of I.S.I., Kolkata.
He is a semi-simple harmonic analyst who works on Tauberian theorems and uncertainty principles.
S. Thangavelureceived his Ph.D from Princeton in 1987. After spending six years in T.I.F.R. and twelve years in I.S.I., he moved to I.I.Sc. in 2005. Recipient of B.M. Birla Science Prize (1996) and Bhatnagar award (2002), he is a Fellow of both Indian Academy of Sciences and Indian National Science Academy. He has authored three books and published more than sixty research papers.