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(1)

CS 101:

Computer Programming and Utilization

Puru

with

CS101 TAs and Staff

Course webpage: https://www.cse.iitb.ac.in/~cs101/

Lecture 19: more Structures, Classes and Objects

(2)

Object Oriented Programming

A methodology for designing programs

(3)

On Design

• Whenever you design something complex, it is useful to have a plan

• Example:

Plan for designing a building:

− Understand the requirements

− Understand the constraints: budget, land area

− Plan how many floors to have

− What should be on each floor

• A plan/methodology is also useful when designing (large) projects

and similarly while designing programs

(4)

Object Oriented Programming

• Understand what is required and write clear specifications (needed in all methodologies)

• Identify the entities involved in the problem

E.g., in a library management program: books, patrons

• Identify the information associated with each entity

− Fixed information: name of the book

− Variable information (state): who has borrowed the book at present

• Organize code so that the entities and their actions/inter relationships are explicitly represented in the code

− Information associated with entities: structure variables

(5)

The C++ structure

• Member variables

− Basic facility provided in C++ to conveniently gather together information associated with an entity

− Inherited from the C language

• Member functions

− New feature introduced in C++

− Actions/operations that effect the entity

− User defined data type with variables and functions

(6)

Defining a structure type

General form

struct structure-type{

member1-type member1-name;

member2-type member2-name;

...

};

// Don’t forget the semicolon!

Example

struct Book{

char title[50];

double price;

};

A structure-type is a user-defined data type, just as int, char, double

are primitive data types

(7)

Nested structures (structure is a data type!)

struct Point{

double x,y;

};

struct Disk{

Point center; // contains Point double radius;

};

Disk d;

d.radius = 10;

d.center = {15, 20};

// sets the x {member of center member of d

(8)

Parameter Passing by Value

struct Point{double x, y;};

Point midpoint(Point a, Point b){

Point mp;

mp.x = (a.x + b.x)/2;

mp.y = (a.y + b.y)/2;

return mp;

}

int main(){

Point p={10,20}, q={50,60};

Point r = midpoint(p,q);

cout << r.x << endl;

cout << midpoint(p,q).x << endl;

(9)

Parameter Passing by Reference

struct Point{double x, y;};

Point midpoint( const Point &a, const Point &b){

Point mp;

mp.x = (a.x + b.x)/2;

mp.y = (a.y + b.y)/2;

return mp;

}

int main(){

Point p={10,20}, q={50,60};

Point r = midpoint(p,q);

cout << r.x << endl;

(10)

Using struct V3

V3 sum(const V3 &a, const V3 &b){

V3 v;

v.x = a.x + b.x; v.y = a.y + b.y; v.z = a.z + b.z;

return v;

}

V3 scale(const V3 &a, double f){

V3 v;

v.x = a.x * f; v.y = a.y * f; v.z = a.z * f;

return v;

}

double length(const V3 &v){

return sqrt(v.x*v.x + v.y*v.y + v.z*v.z);

}

(11)

Member functions

• It is not enough to just define a struct to hold vectors, usually we will also define functions which work on structures/entiries

• In C++, you can make the functions a part of the struct definition itself.

Such functions are called member functions.

• By collecting together relevant functions into the definition of the

struct, the code becomes better organized (object oriented!)

(12)

The Complete Definition of V3

struct V3{

double x, y, z;

double length const(){

return sqrt(x*x + y*y + z*z);

}

V3 sum const(V3 b){

V3 v;

v.x = x+b.x; v.y=y+b.y; v.z=z+b.z;

return v;

}

V3 scale const(double f){

V3 v;

v.x = x*f; v.y = y*f; v.z = z*f;

return v;

}

(13)

One More Example: Taxi Dispatch

• Problem statement: Clients arrive and have to be assigned to (earliest waiting) taxies

• An important part of the solution was a blackboard on which we wrote down the ids of the waiting taxies

• How would we implement this using OOP?

– Create a struct to represent each entity:

– customer, taxi, blackboard?

(14)

The Queue structure

const int N=100;

struct Queue{

int elements[N], nwaiting,front;

bool insert(int v){

… }

bool remove(int &v){

… } };

(15)

Member Function Insert

• A value can be inserted only if the queue has space

• The value must be inserted into the next empty index in the queue

• The number of waiting elements in the queue is updated

• Return value indicates whether operation was successful

(16)

Member Function Insert

• A value can be inserted only if the queue has space

• The value must be inserted into the next empty index in the queue

• The number of waiting elements in the queue is updated

• Return value indicates whether operation was successful

struct Queue{

bool insert(int v){

if(nWaiting >= N) return false;

elements[(front + nWaiting)%N] = v; nWaiting++;

return true;

(17)

Member Function remove

• A value can be removed only if the queue is non-empty

• The value must be removed from the front of the queue. The front should be incremented mod N

• The number of waiting elements in the queue is decremented by 1

• Return value indicates whether operation was successful

struct Queue{

bool remove(int &v){

if(nWaiting < 1) return false;

v=elements[front]; front=(front+1)%N; nWaiting--;

return true;

}

(18)

Main Program

int main(){

Queue q;

q.front = q.nWaiting = 0;

while(true){

char c; cin >> c;

if(c == ‘d’){

int driver; cin >> driver;

if(!q.insert(driver)) cout <<“Q is full\n”;

}

else if(c == ‘c’){

int driver;

if(!q.remove(driver)) cout <<“No taxiavailable”;

else cout <<“Assigning <<driver<< endl;

}

(19)

Remarks

• The member functions only contain the logic of how to manage the queue

• The main program only contains the logic of dealing with taxis and customers

• The new program has become simpler compared to the earlier

version, where the above two were mixed up together

(20)

Structures vs Arrays

• User defined data type, collection of variables of multiple types

• Members can be accessed using the “.” operator

• Structure name denotes the super variable consisting of the entire collection of contained variables

• Structures can be copied using assignments. Also copied when passed by value, or returned from a function

• Member functions can be written to represent actions of the entities represented by the structure

• Collection of variables of single data type

• Members can be accessed using the “[ ]” operator

• Array name denotes pointer to first element of array

• Array elements need to be explicity copied

• Array elements can be accessed by an expression whose value can be computed at run time

(21)

Objects As Software Components

• A software component can be built around a struct

• Just as a hardware component is useful for building big hardware systems,

so is a software component for building large software systems

• A software component must be convenient to use, and also safe,

i.e., help in preventing programming errors

(22)

Packaged software components

• Hardware devices that you buy from the market are packaged, and made safe to use

– Fridge, television : no danger of getting an electric shock.

– A “control panel” is provided on the device. A user does not

have to change capacitor values to change the channel on a

television

(23)

Packaged software components

• Analogous idea for software:

– Make functionality associated with a struct available to the user only through member functions (control panel)

– Do not allow the user to directly access the data members inside a struct. (Just as a user cannot touch the circuitry) The user does not need to know what goes on inside

• If you build a better fridge but keep the control panel the same as the previous model, the user does not need to relearn how to use the new fridge

– If you build a better version of the struct, but keep the

member functions the same, the programs that use the

struct need not change

(24)

The modern version of a struct

• Can behave like a packaged component

• Designer of the struct provides member functions

• Designer of the struct decides what happens during execution of standard operations

• Once structs are designed in this manner, using them becomes convenient and less error-prone

• Structs endowed with above features are more commonly called

objects

(25)

The modern version of a struct

• Designer of the struct decides what happens during execution of standard operations such as:

– Creation of the object – Assignment

– Passing the object to a function

– Returning the object from a function

– Destroying the object when it is not needed

(26)

Structures, Classes and Objects

• Constructors

• Copy Constructors

• Destructors

• Operator overloading

• Overloading the assignment operator

• Access control

• Classes

• Graphics and input/output classes

(27)

The Queue Struct in Taxi Dispatch

const int N=100;

struct queue{

int elements[N],

nWaiting,front;

bool insert(int v){

… }

book remove(int &v){

… }

• Once the queue is created, we expect it to be used only through the member

functions, insert and remove

• Ideally, we do not

expect/want elements,

nWaiting, front to be

directly accessed

(28)

Main Program Using Queue

int main(){

Queue q;

q.front = q.nWaiting = 0;

while(true){

char c; cin >> c;

if(c == ‘d’){

int driver; cin >> driver;

if(!q.insert(driver)) cout <<“Q is full\n”;

}

else if(c == ‘c’){

int driver;

if(!q.remove(driver))

• Main program does use q through operations insert and remove

• However, at the beginning, q.front and q.nWaiting are directly manipulated

• Against the philosophy of

software packaging!

(29)

The Constructor member function

• In C++, the programmer can define a special member function called a constructor which will always be called when an instance of the struct is created

• A constructor has the same name as the struct, and has no return type

• Why useful?

(30)

The Constructor member function

• When q is created in the main program, the

constructor is called automatically

struct Queue{

int elements[N], front, nWaiting;

Queue(){ // constructor nWaiting = 0;

front = 0;

}

// other member functions };

int main(){

Queue q;

// no need to set

// q.nWaiting, q.front

(31)

Constructors In General

struct A{

A(parameters){

… } };

int main(){

A x(arguments);

}

• Constructor can take arguments

• The creation of the object x in main can be thought of as

happening in two steps

– Memory is allocated for x

– The constructor is called on x with the given arguments

• Many constructors possible,

provided they have different

signatures

(32)

Another example: Constructor for V3

struct V3{

double x,y,z;

V3(){

x = y = z = 0;

}

V3(double a){

x = y = z = a;

} };

int main();

V3 v1(5), v2;

• When defining v1, an argument is given

• So the constructor taking a single argument is called. Thus each component of v1 is set to 5

• When defining v2, no argument is given.

• So the constructor taking no

arguments gets called. Thus each

component of v2 is set to 0

(33)

Remarks

• If and only if programmer does not define a constructor, will C++

define a constructor which takes no arguments, and does nothing – If a constructor taking arguments is defined, you implicitly tell

C++ that you want programmers to give arguments.

– if some programmer does not give arguments, C++ will flag it as an error

– If you want both kinds of initialization, define both kinds of constructor

• A constructor that does not take arguments (defined programmer or by C++) is called a default constructor

• If you define an array of struct, each element is initialized using

the default constructor

(34)

The Copy Constructor

• Suppose an object is passed by value to a function

– It must be copied to the variable denoted by the parameter

• Suppose an object is returned by a function

– The value returned must be copied to a temporary variable in the calling program

• By default the copying operations are implemented by copying each member of one object to the corresponding member of the other object

– this default behaviour can be changed by defining a copy

(35)

Example

struct Queue{

int elements[N], nWaiting, front;

Queue(const Queue &source){ // Copy constructor front = source.front;

nWaiting = source.nWaiting;

for(int i=front, j=0; j<nWaiting; j++){

elements[i] = source.elements[i];

i = (i+1) % N;

} };

(36)

Copy Constructor in the Example

• The copy constructor must take a single reference argument:

the object which is to be copied

• Note that the argument to the copy constructor must be a

reference, otherwise the copy constructor will have to be called to copy the argument!

• This is will result in an unending recursion

• Member elements are not copied fully. Only the useful part of it is copied

– More efficient

• More interesting use later

struct Queue{

int elements[N], nWaiting, front;

Queue(const Queue &source){

// Copy constructor

……

(37)

Tracking the use of constructors

struct Queue{

int copyID;

Queue(){

cout << "copyId=" << copyId;

}

Queue(const Queue &source){

copyId = source.copyId;

cout << "copyId=" << copyId;

} };

Queue updateQueue(Queue q){

q.copyId = 3;

return q;

}

int main(){

Queue q;

q.copyId = 1;

Queue r(q);

r.copyId = 2;

Queue z=updateQueue(r);

}

What will be printed?

(38)

Destructors

• When control goes out of a block in which a variable is defined, that variable is destroyed

– Memory allocated for that variable is reclaimed

• You can define a destructor function, which will get executed

before the memory is reclaimed

(39)

Destructor Example

• If a queue that you have defined goes out of scope, it will be destroyed

• If the queue contains elements at the time of destruction, it is likely an error

• So you may want to print a message warning the user

• It is usually an error to call the destructor explicitly. It will be called automatically when an object is to be destroyed. It should not get called twice.

• More interesting uses of the destructor will be considered in later

chapters.

(40)

Destructor Example

struct Queue{

int elements[N], nWaiting, front;

. . .

~Queue(){ //Destructor

if(nWaiting>0) cout << “Warning:”

<<“ non-empty queue being destroyed.”

<< endl;

} };

(41)

Operator Overloading

• In Mathematics, arithmetic operators are used with numbers, but

also other objects such as

(42)

Operator Overloading

• In Mathematics, arithmetic operators are used with numbers, but also other objects such as vectors

• Something like this is also possible in C++!

• An expression such as x @ y where @ is any “infix” operator is considered by C++ to be equivalent to

x.operator@(y) in which operator@ is a member function

• If the member function operator@ is defined, then that is called to

execute x @ y

(43)

Example: Arithmetic on V3 objects

struct V3{

double x, y, z;

V3(double a, double b, double c){

x=a; y=b; z=c;

}

V3 operator+(V3 b){ // adding two V3s return V3(x+b.x, y+b.y, z+b.z); // constructor call }

V3 operator*(double f){ // multiplying a V3 by f return V3(x*f, y*f, z*f); // constructor call

}

(44)

Using V3 Arithmetic

int main(){

V3 u(1,2,3), a(4,5,6), s;

double t=10;

s = u*t + a*t*t*0.5;

cout << s.x <<‘ ‘<< s.y <<‘ ‘

<< s.z << endl;

}

(45)

Remarks

• Expression involving vectors can be made to look very much like what you studied in Physics

• Other operators can also be overloaded, including unary operators (see the book)

• Overload operators only if they have a natural interpretation for the struct in question

• Otherwise you will confuse the reader of your program

(46)

Pointers to Structures

• Disk d1={{2,3},4}, *dptr;

• *dptr is defined to have type Disk, so dptr is a pointer to a variable of type Disk

• Normal pointer operations are allowed on structure pointers

• dptr = &d1;

• (*dptr).radius = 5; //changes the radius of d1

• Operator ->

– (*x).y is same as x->y

• dptr->radius = 5; // same effect as above

(47)

Pointers as Structure Members

struct Disk2{

double radius;

Point *centerptr;

}

Point p={10,20};

Disk2 d;

d.centerptr = &p;

cout << d.centerptr->x << endl; // will print 10.

(48)

The this Pointer

• So far, we have not provided a way to refer to the receiver itself inside the definition of a member function.

• Within the body of a member function, the keyword this points to the receiver i.e., the struct on which the member function has been invoked.

• Trivial use: write this->member instead of member directly struct V3{

double x, y, z;

double length(){

return sqrt(this->x * this->x + this->y * this->y

+ this->z * this->z);

} }

(49)

Overloading The Assignment Operator

• Normally if you assign one struct to another, each member of the rhs is copied to the corresponding member of the lhs

• You can change this behaviour by defining member function operator= for the struct

• A return type must be defined if you wish to allow chained assignments, i.e., v1 = v2 = v3; which means v1 = (v2 = v3);

– The operation must return a reference to the left hand side

object

(50)

Example

struct Queue{

...

Queue& operator=(Queue &rhs){

front = rhs.front;

nWaiting = rhs.nWaiting;

for(int i=0; i<nWaiting; i++){

elements[i] = rhs.elements[i];

i = (i+1) % N;

}

return *this;

} };

(51)

Access Control

• It is possible to restrict access to members or member functions of a struct

• Members declared public: no restriction

• Members declared private: Can be accessed only inside the definition of the struct

• Typical strategy:

Declare all data members to be private, and

some subset of function members to be public

(52)

Access Control Example

struct Queue{

private:

int elements[N], nWaiting, front;

public:

Queue(){ … } bool insert(int v){

..

}

bool remove(int &v){

..

}

(53)

Remarks

• public:, private: : access specifiers

• An access specifier applies to all members defined following it, until another specifier is given

• Thus elements, nWaiting, front are private, while Queue(), insert,

remove are public

(54)

Remarks

• The default versions of the constructor, copy constructor, destructor, assignment operator are public

• If you specify any of these as private, then they cannot be invoked outside of the struct definition

• Thus if you make the copy constructor of a struct X private, then you will get an error if you try to pass a struct of type X by value

• Thus, as a designer of a struct, you can exercise great control over

how the struct gets used

(55)

Classes

• A class is essentially the same as a struct, except:

– Any members/member functions in a struct are public by default

– Any members/member functions in a class are private by

default

(56)

Classes

• Example: a Queue class:

class Queue{

int elements[N], nWaiting, front;

public:

Queue(){…}

bool remove(int &v){…}

bool insert(int v){…}

};

• The members - elements, nWaiting and front will be private.

(57)

Example

struct V3{

double x,y,z;

V3(double v){

x = y = z = v;

}

double X(){

return x;

} };

struct V3{

double x,y,z;

V3(double v);

double X();

};

//implementations V3::V3(double v){

x = y = z = v;

}

double V3::X(){

return x;

}

(58)

Concluding Remarks

• The notion of a packaged software component is important.

• Making data members private: hiding the implementation from the user

• Making some member functions public: providing an interface using which the object can be used

• Separation of the concerns of the developer and the user

• Idea similar to what we discussed in connection with ordinary functions

– The specification of the function must be clearly written down (analogous to interface)

– The user should not worry about how the function does its

(59)

Input Output Classes

• cin, cout : objects of class istream, ostream resp. predefined in C++

• <<, >> : operators defined for the objects of these classes

• ifstream: another class like istream

• You create an object of class ifstream and associate it with a file on your computer

• Now you can read from that file by invoking the >> operator!

• ofstream: a class like ostream, to be used for writing to files

• Must include header file <fstream> to uses ifstream and ofstream

(60)

Example of file i/o

#include <fstream>

#include <simplecpp>

int main(){

ifstream infile(“f1.txt”);

// constructor call. object infile is created and associated

// with f1.txt, which must be present in the current directory ofstream outfile(“f2.txt”);

// constructor call. Object outfile is created and associated

// with f2.txt, which will get created in the current directory

(61)

Example of file i/o

repeat(10){

int v;

infile >> v;

outfile << v;

}

// f1.txt must begin with 10 numbers. These will be read and // written to file f2.txt

}

(62)

“String theory”

• Iterative computations are demonstrated well on arrays

• strings … luckily the system manages the array space for us

• Can assign and append to strings

• Can read a position: cout << message[px]

• Can write a position: message[px] = ‘q’

• That’s all we need for now

(63)

Printing a string in reverse

string message;

getline(cin, message);

int mx = message.size()-1;

while (mx >= 0) {

cout << message[mx];

--mx;

}

• mx updated in a completely predictable way Ideal candidate to write as for loop

Character at position mx in

string

message

(64)

Finding needles in a haystack

• Given two strings, needles and haystack

• needles has no repeated characters

• haystack may repeat characters

• How many characters in needles appear in haystack at least once?

• needles = “bat”, haystack = “tabla” à 3

• needles = “tab”, haystack = “bottle” à 2

(65)

One needle in a haystack

• Subproblem: given one character ch and a string find if ch appears in string at least once

char ch; // suitably initialized

string haystack; // suitably initialized int ans = 0; // will change to 1 if found

for (int hx = 0; hx < haystack.size(); ++hx) { if (ch == haystack[hx]) {

++ans;

break; // quit on first match }

}

(66)

Many needles: nested loop

main() {

string needles, haystack;

getline(cin, needles); getline(cin, haystack);

int ans = 0;

for (int nx=0; nx < needles.size(); ++nx) { char ch = needles[nx];

for (int hx = 0; hx < haystack.size(); ++hx) { if (ch == haystack[hx]) {

++ans;

break; // quit on first match

} Generalize to work in

(67)

Duplicate needles

• needles = “bat”, haystack = “tabla” à 3

• needles = “tab”, haystack = “bottle” à 2

• needles = “bata”, haystack = “tabla” à 3

• Two approaches

– Dedup needles before executing earlier code (reducing to known problem)

– Dedup needles “on the fly” (inside the nx loop) Exercise: If the input strings have n and h

characters, at most how much time does

the needle-in-haystack search code take?

(68)

Generalize to arbitrary lengths

• “Hello” < “Help” but “Hello” > “Hell”

• Scan both strings from the beginning

• If differing character found, same as before

• If a string ends, it is “less” than the other

int ans=0, ax=0, bx=0, an=as.size(), bn=bs.size();

for (; ans==0 && ax < an && bx < bn; ++ax, ++bx) { if ( (ans = as[ax] – bs[bx]) != 0) break;

}

if (ans == 0) { This results in an arbitrary integer as

the return value in case of unequal

(69)

break

while (true) {

ans += base/fac;

base *= x;

fac *= (++ix);

if (base/fac < epsilon) { break;

}

cout << (base/fac) << endl;

Terminates immediately

enclosing

while loop

References

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